Re: Hydroelectric Power

Mishagam wrote:
Wonderer wrote:
This is useful information for my understanding. However, the pages
did not mention the flow of water in gallons/minute needed for a given
wattage. I understood the part about the head configuration. If you
were to have a cistern on your roof, how many gallons would it have to
hold to say generate 1kw continuously for one hour. A gallon of
gasoline can generate 1kw continuously for eight hours in a small
internal combustion engine. Reversing the flow of water would fill up
the cistern on the roof.

I think we can calculate this. 1 gallon on roof (assume roof height is 4 meter - about 13 feet) has energy:
E = m*g*h = 4kg * 10 * 4 = 160 joule.
1 kWh = 1000 * 3600 = 3600000 joule.

So you need 3600000 / 160 = 22500 gallons = 90 m3

I doubt average roof will be able to hold so much water.
Good news is that average daily use of water in HH is 70 gallons (first found number from Google), so this amount will be almost enough for water use for one year.

I think 90 m3 is decent size swimming pool - 9 * 5 * 2 m3.
.

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