Re: Perpetum Mobile Idea #358


"gb" <gb6726@xxxxxxxxx> wrote in message news:9a2268af-1df2-4bc6-94ea-8acb0e6bf181@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
This idea is based on Perpetum Mobile Idea #357.

We have a pipe running up, and the pipe has water. Anything inserted
into the bottom of the pipe into this water will float up in the pipe
to the top. The point is to loose less weight in the water loss at the
bottom of the pipe than the weight that manages to rise inside the
pipe filled with water. Objects inserted rise as they are lighter than
water, and water loss at the bottom of the pipe when inserting objects
may cause down pressure in the pipe, but the objects lighter than
water need to move quickly and pop out of the pipe at the top, then
use their weights to come back down and generate electricity.

One is constantly stuffing objects in at the bottom of the pipe and
water gently escapes. The objects rush up in the water. Water is
running from up down in the pipe, objects are stuffed into the pipe on
the bottom. The objects must race to beat the weight that is lost with
their weights making to the top.

Suppose you arrange a perfect air-lock at the bottom of the pipe. So when you open the hatch, and put in a ball, there is exactly zero room for water. You close the hatch and open the other side so the ball can float up the pipe to the surface.

Oops, now your air-lock is full of water. You shut the hatch on the pipe side and want to open the air side hatch so you can put in a second ball. If you just open the air-side hatch, all that water will spill out and you'll have to collect it up to put back into the pipe. Or you use some sort of pump-down system to pump the water from the air lock into the pipe. Either way, you use energy to put the water back into the pipe before you can put the second ball into the air lock. Care to guess how much energy it will take to put the amount of water displaced by one ball back into the pipe?

TANSTAAFL ("The Moon is a Harsh Mistress", Heinlein)

daestrom

.

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