Re: mandelbrot in imaginary space

In article <1119503697.978471.66110@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>,
effbiae <effbiae@xxxxxxxxx> wrote:

> oh well, i thought i was onto something...
>
> but i don't see how the complex plane can contain sqroot(-i). in my
> (primitive) understanding, the point (x,y) in the complex plane is x +
> iy where x and y are real.
>
> now finding x and y for sqroot(-i):
> x+iy=sqroot(-i)
> =sqroot(-1.i)
> =i.sqroot(i)
> therefore x is zero and y is sqroot(i) which is not real.
> is the complex plane more general and can y have imaginary values?
>
> thanks, jack
>

let x=-1/sqrt(2) and y=1/sqrt(2).
Then both x and y are real.
Compute (x+iy)^2 = -i
Did you get that?

--
G. A. Edgar http://www.math.ohio-state.edu/~edgar/
.

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