Re: Gravitational Bohr Radius
- From: Robert <rloldershaw@xxxxxxxxxxx>
- Date: Wed, 19 Sep 2007 16:35:12 -0700
On Sep 19, 2:43 pm, Robert <rlolders...@xxxxxxxxxxx> wrote:
Want to see something interesting?
The Gravitational Bohr Radius is the radius that the hydrogen atom
would have if it were dominated by the gravitational "force".
Technically, R = h(bar)/G m^2 M, where R is the GBR, h(bar) is
Planck's constant divided by 2 pi, G is the gravitational "constant",
m is the mass of the electron, and M is the mass of the proton.
If you calculate R using the conventional value of G, you get R ~ 1.2
x 10^31 cm! Bizarre!
If you calculate R using the correct value G` that applies within
Atomic Scale systems and is equal to 2.18 x 10^31 cgs, then R ~ 3.67
x
10^-8 cm, or about 2 pi times the Bohr Radius.
If you are interested in seeing where this mysterious G` comes from,
and how the scaling of G for the Discrete Fractal Paradigm can
correctly retrodict the radius of the proton, or of an atom, or of a
pulsar, or of a star, or of a galaxy, or ..., then go towww.amherst.edu/~rloldershaw
and have a look.
Be sure to check out the latest "New Development", which uses G` to
finally explain the meaning of the fine structure constant.
Enjoy,
Knechtwww.amherst.edu/~rloldershaw
Let me just add that when you use G' to recalculate the Planck scale,
the Planck mass, length and time are all closely associated with the
mass, length and time scales associated with the proton. For the
recalculation see: www.amherst.edu/~rloldershaw , "Technical Notes"
section, "Revised Planck Scale".
Contrast those results with the strange and seemingly random results
one gets for the "conventional" Planck scale using G, e.g., ~10^-33
cm(!), ~10^-5 g(!!!), and ~10^-44 sec(!).
Could most of theoretical high energy physics be based upon a
steaming
pile of bad assumptions?
Worth thinking about,
Knecht
-- www.amherst.edu/~rloldershaw --
.
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