Re: chain codes

I presume you've already figured this out since the answer is so
simple, but. . .
Your code doesn't compute chain codes at all. It merely follows
borders in the image and builds up an edge detection image, kind of
like you ran a Sobel filter over it. So you have an image with edges
in it, but you're not keeping track of the individual edges. Keep at
it and you'll get it.

By the way, your code only processes one "image" which may have
several "blobs" in it. If you have another image with another circle
in it, you'll have to open each image file individually and process
each file in turn.
Regards,
ImageAnalyst


On Feb 7, 12:58 pm, "cindy" <olivemckenzie2...@xxxxxxxxx> wrote:
I would like to known if any one can describe to me how to read the
chain code of two circles side by side in a image and how do I would
know when one image has finished and another image has begun. using C+
+ code. I have tried the typical neighbourhood code and it does not
seem to work.

for(int h=1; h<ROWS-1;h++)
{
for(int w=1; w<COLS-1;w++)
{
int value=Array[h][w];

if (val<255)
cout<<h<<" " <<w<<endl;

getchar();

if(Array[h][w]<255)
{
Shape_Array[h][w] = value;
}
else
if (Array[h][w+1] < 255 && Shape_Array[h][w+1] == 255)
{
Shape_Array[h][w+1] = value;
w++;
}
else if (Array[h][w-1] < 255 && Shape_Array[h][w-1] == 255)
{
Shape_Array[h][w-1] = value;
w--;
}

else
if (Array[h+1][w-1] < 255 && Shape_Array[h+1][w-1] == 255)
{
Shape_Array[h+1][w-1] = value;
h++;
w--;
}
else if (Array[h+1][w] < 255 && Shape_Array[h+1][w] == 255)
{
Shape_Array[h+1][w] = value;
h++;
}
else if (Array[h+1][w+1] < 255 && Shape_Array[h+1][w+1] == 255)
{
Shape_Array[h+1][w+1] = value;
h++;
w++;
}
else if (Array[h-1][w-1] < 255 && Shape_Array[h-1][w-1] == 255)
{
Shape_Array[h-1][w-1] = value;
h--;
w--;
}
else if (Array[h-1][w] < 255 && Shape_Array[h-1][w] == 255)
{
Shape_Array[h-1][w] = value;
h--;
}
else if (Array[h-1][w+1] < 255 && Shape_Array[h-1][w+1] == 255)
{
Shape_Array[h-1][w+1] = value;
h--;
w++;
}

}
}


.