Re: $B87$7$$;~Be$r$b$&2a$.$^$7$?(B
From: M_SHIRAISHI (eurms_at_fancy.ocn.ne.jp)
Date: 01/09/05
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- In reply to: Marc Adler: "Re: $B87$7$$;~Be$r$b$&2a$.$^$7$?(B"
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Date: Sun, 09 Jan 2005 10:57:56 +0900
Marc Adler wrote:
> M_SHIRAISHI wrote:
>
> > That IS alright. However, $B!V87$7$$;~4|(B*$B$O(B*$B2a$.$F!":#$O50F;$K>h$j$^$7$?!#!W(B
> > is also alright. No problem at all --- I can assure you.
>
> But you said that it had to be $B$O(B, and not $B$r!#(BI provided examples to
> the contrary.
>
> > $B!VF|K\7P:Q$O!"%P%V%kJx2u8e$N87$7$$;~Be$O2a$.$F!"@.D9N($,%P%V%kA0$N1>!9!D!W(B
> > is a perfect Japanese sentence.
>
> What would be the difference between $B$O(B and $B$r(B here, then?
I think there is only a very subtle difference.
If you use "$B$r(B", then the correspondent sentence means that you will no longer
experience "$B87$7$$;~4|(B", On the other hand, if you use "$B$O(B", then the
correspondent
sentence means that you might have no more so much "$B87$7$$;~4|(B", but you must
prepare another "$B87$7$$;~4|(B", it might not be so much severe one though.
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