Re: Universal grammar

In article <87hcvzs5nq.fsf@xxxxxxxxxxxxxxxxxxxxxxxxxx>, LEE Sau Dan
<danlee@xxxxxxxxxxxxxxxxxxxxxxxxxx> wrote:

Hans> Do you agree that electricity and magnetism are the same,
Hans> not merely being equivalent by a simple formula consisting
Hans> of a two-form and some straightforward Lorentz
Hans> transformations?

Yes. And there is no basic "magnetic charge" in physics. Magnetic
dipoles are now explained by orbiting or spinning charges. So, it all
boils down to charges and their motion.

With the same view, there is no equation E = mc^2, only rest mass and
energy momentum. The E and the m of this equation are observed quantities,
just as the electric and magnetic fields. And there is only timespace, as
time and distance are also wholly observational data.

And setting c = 1 not only makes energy and mass equivalent, but also time
and space, measurable in seconds. In addition to that, setting the gravity
constant G = 1 also makes mass measurable in seconds. And similarly for
constants in the Maxwell equation for EM fields, and in QM, one can set /h
= 1 as well. Commonly used in theoretical equations.

The equation E = m c^2 only deals with the equivalence between kinetic
energy and mass. There is also potential energy, like when you lift a mass
in a gravitational field to a new position.

BTW, have you ever heard of gravitomagnetism?  It's the counterpart of
magnetism for mass (gravitational field).

      http://en.wikipedia.org/wiki/Gravitoelectromagnetism

No, though I once looked at GR angular momentum. Thank you for the link.

Perhaps this might be of use as an input:

The form of the Maxwell equations I prefer uses the Clifford algebra. In
GR, EM is expressed using a 2-form F, a potential A, and a current J
subject to the equations:
  dA = F, div A = 0, dF = 0, div F = J, div J = 0
When these fields are mapped into the Clifford algebra C(g), these
equations can be reduced to
  /d A = F,  /d F = J
where /d is the Feynman slash indicating Clifford multiplication. (I have
set c and epsilon_0 to 1; otherwise replace J with J/(epsilon_0 c).)

Now take a spin representation of C(g); then the form of the Dirac
equation given in Itzykson & Zuber, "Quantum Field Theory", equation
(2-74), gets the form
  i /d psi = (m + e /A - Delta g_m/2 e/4m i /F) psi
Setting the gyro-magnetic ratio g_m = 0 gives the common Dirac equation.

In a GR context, one should note that psi can be constructed within the
differential forms bundle, on which the Levi-Civita connection is trivial.
This means that, if modeled this way, there are no need for GM gravity
corrections to the Dirac equation.

--
Hans Aberg
.

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