Re: Longest word in Chinese



On Sep 16, 4:57 pm, LEE Sau Dan <dan...@xxxxxxxxxxxxxxxxxxxxxxxxxx>
wrote:
"Richard" == Richard Wordingham <jrw0...@xxxxxxxxxxx> writes:

>> On Sep 16, 10:10 am, "Helge S" <helg...@xxxxxxx> wrote:
>>> A very long word is: Mengtesailatedao consisting of 6
>>> characters and meaning (the Island of) Montserrat.

Richard> And how could it be shorter than the transliteration of
Richard> Llanfairpwllgwyngyllgogerychwyrndrobwllllantysiliogogogoch
Richard> ? :)

That's still shorter than:

Zhong1hua2ren2min2gong4he2guo2Xiang1gang3te4bie2xing2zheng4qu1-
xing2zheng4zhang3guan1ban4gong1shi1

Try this town in New Zealand (googlable):

Tetaumatawhakatangihangakoauaotamateaurehaeaturipukapihimaungahoronukupokaiwhenuaakitanarahu

or this town in Thailand (un-googlable up to now, because the word is
usually into several lines):

Krungthepmahanakornamornratanakosinmahintarayutthayamahadilokphopnopparatrajathaniburiromudomrajaniwesmahasatharnamornphimarnavatarnsathitsakkattiyavisanukamprasit

or alternatively (I don't know which spelling is correct, I cut and
pasted from two sources):

Krungthepmahanakonbowornratanakosinmahintarayudyayamahadiloponoparatanarajthaniburiromudomrajniwesmahasatarnamornpimarnavatarsatitsakattiyavisanukamphrasit

-- Ekki

.



Relevant Pages

  • Re: Enigma 1362 - Eight-fifths
    ... > to be done except the same enumeration of possibilities that Richard ... > I'm instead inclined to complain that the puzzle isn't interesting. ... I will agree, however, that yours is shorter. ... extra few seconds it took to type the extra characters in my source file. ...
    (rec.puzzles)
  • Re: Help from fellow Fortran Users
    ... > I think the only cases he actually spoke of were for shorter actual ... > arguments than dummies, Richard. ...
    (comp.lang.fortran)
  • Re: Longest word in Chinese
    ... Richard> And how could it be shorter than the transliteration of ... That's still shorter than: ... Krungthepmahanakornamornratanakosinmahintarayutthayamahadilokphopnoppar ...
    (sci.lang)