Re: No Unique Initial Segment And No Characteristic Expansion

From: HERC777 (herc777_at_hotmail.com)
Date: 12/07/04 

Date: 7 Dec 2004 01:26:34 -0800

That's my point, you don't show the member is unique, you just define
it so.

c1=!f1,1 & c2=!f2,2 &...

Therefore

c1!=f1,1 & c2!=f2,2 &..

WOW big conclusion.

but your definition is flawed.

your argument, assume sequence is at n, cn!=fn,n is self referential,
its completely meaningless, no different to Russels paradox or many
others. define a number that is not a number, what do you have?

So how did you conclude the sequence is original? by changing digits?
every digit in every digit position is saturated, its not going to run
out of options.

THINK this time, any 10 year old can work this out.
Infinite people all toss coins infinite times each.
Can you come up with a new sequence of heads and tails?

The diagonal is not going to help here. All combinations to infinite
length are done.

Lets drop infinity and go by the book, only allow assertions about
large objects as they tend to infinity.

Many people toss coins many times each. How many coins do you have to
toss in sequence, to eventually get a new sequence?

log(number of people).

As number of people -> oo, log(number of people) -> oo.

All sequences have been done to infinite length, you need MORE THAN
INFINITE flips to succeed.

A sequence has a HEAD and a TAIL.

The diagonal of a random infinite list has NO UNIQUE INITIAL SEGMENT in
the head and NO CHARACTERISTIC EXPANSION i the tail. There is nothing
to distinguish the diagonal from members of the list.

The diagonal of UTM(X, Y) has NO UNIQUE INITIAL SEGMENT and NO
CHARACTERISTIC EXPANSION to distinguish it from members of the list.

Infinite means NEVER ENDING.
Infinite means NEVER COMPLETED
If you try to prove INFINITY is not complete you get TRUE.

Herc

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