My claim on Omega's defn
From: |-|erc (H_at_r.c)
Date: 01/30/05
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Date: Sun, 30 Jan 2005 16:11:13 +1000
Omega = sum( p halts) 1 / (2 ^ size(p))
Program Size
1 1
2 1
3 2
4 2
5 3
6 3
7 3
8 3
9 4
..
If all programs halt
Omega = 1/2 + 1/2 + 1/4 + 1/4 + 1/8 + 1/8 + 1/8 + 1/8 + 1/16..
= 1 + 1/2 + 1/2 + 1/2 ...
= oo
Say there is a fixed constant for which this fraction of programs halt.
Let the percentage of programs that halt be 0.01%.
Omega = Omega(|p|=1) + Omega(|p|=2) + Omega(|p|=3) + ...
Omega(|p|=3) is half the probability that a program of size 3 will halt.
There are 4 programs of size 3, p = 5, 6, 7, 8.
If one of them halts then
Omega(|p|=3) = 1 / (2 ^ 3) = 1/8.
i.e. 25% of programs halt of size 3.
consider Omega(|p|=1,000,001) + Omega(|p|=1,000,002) + ... + Omega(|p|=2,000,000)
If on average 0.01% of programs halt, then each term is 1/2 * 0.01% = 0.00005.
there are a million terms, so Omega is greater than 1,000,000 * 0.00005 = 50.
Even with infinitesimally small total probability of halting, Omega will not converge and will equal oo.
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Now try the modified Omega.
If all programs halt
Omega' = 1/4 + 1/4 + 1/16 + 1/16 + 1/64 +1/64 + 1/64 + 1/64 + 1/256 + ..
= 1/4 + 1/4 + 1/8 + 1/16 + 1/32...
= 0.75
You could dissalow the 1st program, 0, so it adds to 1.
Omega' = sum (p halts) 2 ^ (-2 |p| )
Herc
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