Re: Set Theory Exercise


William Elliot wrote:
> On Sat, 25 Jun 2005, Max Weiss wrote:
>
> > Well, I was hoping to avoid controversy...
> >
> > Do you mean that you think that the argument is o.k.?
> >
> As you have removed all context not keeping or quoting anything from the
> post your replying to, it's not clear to whom you are replying or what you
> are talking about. Please don't remove context, it leads to gibberish.
>

Sorry about that! I was wondering whether your remark

> Thus you've show Exercise ==> AxC. So hurry up and do that exercise

indicated you thought correct my earlier

> Let x be a set, and let S = {x}. Then Pow(S)={{x},0}, so there is a
> choice function for S, namely {<{x},x>}. But then by the Exercise
> there's a choice function for union(S), i.e., for x

Cheers,

Max

.

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