Re: What is the 1st order formal system known as PA?
- From: Nam Nguyen <namducnguyen@xxxxxxx>
- Date: Mon, 28 Nov 2005 17:56:47 GMT
Rupert wrote:
Nam Nguyen wrote:
Rupert wrote:
Nam Nguyen wrote:
What I propose is very much similar. There would be many "PA[-ish]" theories under the proposal, all of which would share the same unary [successor] function symbol "S".
So by a PA-ish theory you just mean an extension of PA?
No. Under my proposal, there is no lone PA theory to be extended from.
There is a standard definition of PA and there's only one theory that satisfies it.
Care to prove that there is only one theory *satisfying* the standard definition of Peano axioms? Or is that because "Philosophically, it's completely obvious", again?
Instead, there are many PA-ish theories all having the same language L(PA), satisfying Peano axioms [which means all have the same successor function symbol "S", among other things.] Note that _here_, in "L(PA)", "PA" doesn't denote a theory!
Well, obviously you're going to have to give a definition of "PA-ish" theory if we're going to be able to know what you're talking about.
I've just given so, the very paragraph right above! Did you really read that paragraph?
There's no such thing as an axiom we could not state.
Would you care to provide a proof for your meta statement above?
The notion "we can state it" is not a mathematical one, so I can't give a mathematical proof. Philosophically, it's completely obvious. An axiom is just a certain kind of string of symbols. Any axiom of reasonable length, we can state. I suppose an axiom might be too long for us to state. But I don't think that's what you had in mind.
Regardless of why you don't think that's what I had in mind, would you concede now that there are axioms we couldn't state [i.e. anonymous axioms]?
If you don't, then your tendency of making assertions [or refuting people's statements] without concrete proof, and of not following what people have just said seems to make our conversation in this thread hit a dead-end. And I'd probably have to leave it at that!
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