Re: Request for Peer Review - Refutation of Cantor Theorem Conclusion


Scott wrote:
george wrote:

Dip***: If the set only has TWO elements, then making
a SQUARE list of the subsets means you only get to put
TWO subsets on your list. And SINCE THERE ARE FOUR,
I can ALWAYS find one (The third or the fourth) that is NOT
ON YOUR LIST. The subsets are intended to be represented
by bit-strings, once you have ordered the elements in the set.
In the order that you enumerated it, YOUR list is
00
10
01
11

Which is 4x2, NOT 2x2, and NOT square.

No, dip***, *you* are not getting it. It is an enumeration, not a
mapping.

Dip***: EVERY ENUMERATION IS
a mapping! To "enumerate" a set MEANS
to MAP its elements, 1-1, onto some initial segment
of the natural numbers! This associates A NUMBER with
every element of the set! THAT'S WHY IT'S CALLED an
ENUMERATION!

.

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