Re: FOL & completeness




"MoeBlee" <jazzmobe@xxxxxxxxxxx> wrote:
iff, for a first order theory

The other direction is usually called the 'soundness theorem'. So "iff"
is equivalent to the conjunction of the completeness and soundness
theorems.


Of course.




The incompleteness theorem is that for any consistent, recursive set of
axioms, there is a sentence that is true in the standard model of
number theory (but NOT true in all models) that is not provable from
said axioms.

So, can we say that the same Goedel theorem affirms that G is not
logically
valid ?

I don't think the parenthetical part "(but NOT true in all models)" is
usually mentioned as itself a clause in the incompleteness theorem. I
just added the parenthetical to highlight for you the difference
between the completeness theorem (which addresses formulas that are
satisfied by every model, (or, for sentences, that are true in every
model)) and the incompleteness theorem (which addresses sentences that
are true in the standard model of number theory, but which, I'm
parenthetically now adding, are not necessarily true in all models and
which we can see that they are not true in all models).

That such sentences are not true in all models follows from the
completeness theorem. If a sentence is not provable from certain sets
of axioms, then the sentence is not valid.


Ok, that is just what I meant with my question. Thank you.

P.S. I wonder what could be model of PA in which G does not hold...


.



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