Re: Every set x equinumerous with a set y disjoint from x?
- From: "MoeBlee" <jazzmobe@xxxxxxxxxxx>
- Date: 28 Aug 2006 09:44:54 -0700
Frederick Williams wrote:
"David C. Ullrich" wrote:
Without AC I'm not sure what card even means.
See Suppes well-known text! (Iirc he follows Tarski.)
Thank you. That is pretty much the kind of approach I had in mind. One
can use card comparisons just to assert the existence or non-existence
of injections. I don't prefer that kind of notation, and my original
problem didn't use it; but I used it subsequently since it was already
in play in the thread, in a context where I've been asking how to prove
without choice.
MoeBlee
.
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