Re: Finding models to a formula
- From: "Konrad Viltersten" <tmp1@xxxxxxxxxxxxxx>
- Date: Fri, 15 Dec 2006 20:12:48 +0100
Given is the formulaNo, there is no disproof as there's a model.
AxAyAz:(x=y OR y=z OR x=z), where A is "for all"
The models i've found are on form:
"any model with not more than two elements".
Could the above statement be contradicted? Can it be
completed by additional models?
The only models are those with universe set of one or two elements.
Thanks for the answer.
--
Vänligen
Konrad
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