Re: wittgensteins Tractarian logic any suggestions.?
- From: G. Frege <nomail@invalid>
- Date: Fri, 23 Feb 2007 01:23:00 +0100
On Wed, 21 Feb 2007 19:00:10 +0100, G. Frege <nomail@invalid> wrote:
_It seems that § refers to (certain) statements. Let's write
TLP 5.52
"If § has as its values all the values of a function fx
for all values of x then
_
N(§) = ~(Ex).fx."
(a) § ==> P
if § refers just to the statement P ("has P as its value"). And
(b) § ==> P, Q, R
if § refers just to the statement P, Q, R ("has as its values P, Q,
R). Finally:
(c) § ==> fx for all x
if § "has as its values [refers to] all the values of a function fx
for all values of x".
Consider -for example- the function fx : "x is a man".
(If our universe of discourse would only consist of finitely many
objects, say, a, b, c, then this would amount to § ==> fa, fb, fc.)
Now Wittgenstein writes
_
N(§)
to express the "conjunction" (in the finite case) of the negations of
all the statements § refers to.
"5.502 N(§) is the negation of all the values of the [...]
variable §."
_
Hence in case of (a) we would have:
_
N(§) = ~P.
In case of (b) we would have:
_
N(§) = ~P . ~Q . ~R.
"5.51 If § has only one value, then N(§) = ~p (not p), if it
_
has two values then N(§) = ~p . ~q (neither p nor q).
And in case of (c) [following Wittgenstein] we would have:
_
N(§) = (x).~fx ,
or equivalently
_
N(§) = ~(Ex).fx.
(If our universe of discourse would only consist of finitely many
objects, say, a, b, c, then this would amount to
_
N(§) = ~fa . ~fb . ~fc ( = (x).~fx in this case) ,
or
_
N(§) = ~(fa v fb v fc) (= ~(Ex).fx in this case). )
Funny coincident (I just stumbled over). "Owen" wrote (at some other
place):
"N(p) = (p nor p) = ~p.
N(p,q) = (p nor q) = ~p & ~q.
N(p,q,r) = ~p & ~q & ~r.
N(Fa,Fb,Fc,...) = ~Fa & ~Fb & ~Fc & ... = ~ExFx.
etc."
This seems to "confirm" my own analysis. :-)
F.
--
E-mail: info<at>simple-line<dot>de
.
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