Re: infinitely many nn's = infinite nn's?
- From: G. Frege <nomail@invalid>
- Date: Sat, 10 Mar 2007 01:06:15 +0100
On Thu, 8 Mar 2007 14:37:29 -0500, David Marcus
<DavidMarcus@xxxxxxxxxxxxxx> wrote:
Sure he is a crank.He self-published his own book. He most definitely is a crank.
Much to my surprise I found that he's not the
non-math crank I expected, but a published author.
"My goal is to show that set theory is self contradictory,
in particular Cantor's claim of the infinite set of finite
naturals. This goal is not difficult to achieve. There are
several proofs." (WM)
"This goal is not difficult to achieve"? Sure if one is completely
incompetent concerning mathematics --- sounds EXTREMELY reasonable!
Well, they had to wait for Mückenheim (to come)!That's a good one. So, the fact that the rationals are dense implies the
By the way, a proof that the irrationals are not uncountable is
already established by the observation that there is no pair of
irrational numbers which is not separated by a terminating rational
number.
reals are countable. I wonder how all the mathematicians missed that
theorem.
F.
--
E-mail: info<at>simple-line<dot>de
.
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