Re: Cantor's circular "proof" that evens = integers



In article <1sto331ke4sq6f8k1jjb26su865pq7vi9s@xxxxxxx>,
G. Frege <nomail@invalid> wrote:

On Sat, 05 May 2007 09:11:59 GMT, Phil <toob-headman@xxxxxxxxxxxxx>
wrote:


Now, if anyone can PROVE that whenever x is in N, then 2*x is in N,
then you have a true PROOF that N and E are equinumerous.

If you weren't the idiot you are, you might notice that * is an
operation which can be (and is) defined in set theory, such that
n*m in N for all n,m e N. Since 2 e N this implies that 2*n in N
for all n e N.

If you are curious, * is defined the following way:

(a) n * 0 = 0
(b) n * m' = n * m + n

Or if one insists that N begins with 1, as Phil seems to want to do,
one first defines addition, (+) inductively as
(a) n + 1 = succ(n)
(b) n + succ(m) = succ(n + m)
the one gets multiplication (*) indiuctively by
(c) n*1 = n
(d) n*succ(m) = n*m + n.
It is then trivial to prove, again inductively, that both (+) and (*)
are closed operations , i.e., that all sums and products of naturals are
again naturals.


However, simply claiming that "this is obvious" is not adequate [...]

The detailed proofs are trivial, but tedious. If you want them, get a
text on foundations, and do a little of the work on your own.

No-one (other than you) suggests that the claim "this is obvious"
is an adequate replacement for an explicit mathematical proof.

That there are many texts on foundations of mathematics which contain
all these proofs, and more besides, makes it obvious that anyone who
wants such proofs can get them.

If you want tutoring, are you willing to pay the going rates for it?



Actually, WE all know that

"Unproven statements carry little weight in the world
of mathematics." (Amir D. Aczel)

Those statements are proven in many places. That Phil does not have
access to those proofs is largely his problem.
.



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