Re: Answer "how to prove ~(P <--> Q) |- ~P <-->Q "
- From: herbzet <herbzet@xxxxxxxxx>
- Date: Sat, 02 Jun 2007 01:37:11 -0400
"Jesse F. Hughes" wrote:
herbzet writes:
My copy doesn't have CP. What is CP?
Conditional proof (sometimes called -> intro).
Assume P. Derive Q. Conclude P -> Q.
Thank you.
--
hz
--
Posted via a free Usenet account from http://www.teranews.com
.
- Follow-Ups:
- Re: Answer "how to prove ~(P <--> Q) |- ~P <-->Q "
- From: George Dance
- Re: Answer "how to prove ~(P <--> Q) |- ~P <-->Q "
- References:
- Re: Answer "how to prove ~(P <--> Q) |- ~P <-->Q "
- From: herbzet
- Re: Answer "how to prove ~(P <--> Q) |- ~P <-->Q "
- From: Jesse F. Hughes
- Re: Answer "how to prove ~(P <--> Q) |- ~P <-->Q "
- Prev by Date: Re: Subsets of cardinals in a well-ordering
- Next by Date: Re: Answer "how to prove ~(P <--> Q) |- ~P <-->Q "
- Previous by thread: Re: Answer "how to prove ~(P <--> Q) |- ~P <-->Q "
- Next by thread: Re: Answer "how to prove ~(P <--> Q) |- ~P <-->Q "
- Index(es):
Relevant Pages
|
Loading