Re: Largest Set in ZFC?
- From: "Peter Webb" <webbfamily@xxxxxxxxxxxxxxxxxxxxxxxxx>
- Date: Sun, 9 Mar 2008 03:45:28 +1100
<SNIP>
> The definition is:
> {S} = {S S}
> and, of course {S S} we get from pairing..
Thanks. I was curious how that worked.
If S is a set then pairing says {S,S} is a set
and extensionality says {S,S} = {S}.
*** I had never even noticed the issue, interesting.
It seems AoI is deliberately vague about what
sets are members of X. Why is that?
I don't know the motivation of the actual people who wrote it, but the
reason I personally would give is this: We don't NEED to be any more
specific, since separation does the rest of the job for us to get to
the specific set w that we want.
*** I know much less about this topic than you do, but it seems there is a more fundamental reason for the vagueness of the definition of X. If anybody could produce a specific such X, then they would have a model of ZF (a collection of sets that satisfy ZF). This would prove the consistency of ZF. AFAIK, there is no theoretical reason why such a set X could not be described, but none ever has, and its seems pretty obvious that none ever will. Hence the requirement to vague it up a bit.
.
- Follow-Ups:
- Re: Largest Set in ZFC?
- From: MoeBlee
- Re: Largest Set in ZFC?
- From: reasterly
- Re: Largest Set in ZFC?
- References:
- Largest Set in ZFC?
- From: reasterly
- Re: Largest Set in ZFC?
- From: MoeBlee
- Re: Largest Set in ZFC?
- From: reasterly
- Re: Largest Set in ZFC?
- From: MoeBlee
- Largest Set in ZFC?
- Prev by Date: Re: Is peano arithmetic inconsistent under the intended interpretation?
- Next by Date: Re: Semantics of First-Order Languages
- Previous by thread: Re: Largest Set in ZFC?
- Next by thread: Re: Largest Set in ZFC?
- Index(es):
Relevant Pages
|