Re: Largest Set in ZFC?
- From: reasterly@xxxxxxxxx
- Date: Sat, 8 Mar 2008 13:08:06 -0800 (PST)
On Mar 8, 8:45 am, "Peter Webb" <webbfam...@xxxxxxxxxxxxxxxxxxxxxxxxx>
wrote:
The definition is:
{S} = {S S}
and, of course {S S} we get from pairing..
Thanks. I was curious how that worked.
If S is a set then pairing says {S,S} is a set
and extensionality says {S,S} = {S}.
*** I had never even noticed the issue, interesting.
It seems AoI is deliberately vague about what
sets are members of X. Why is that?
I don't know the motivation of the actual people who wrote it, but the
reason I personally would give is this: We don't NEED to be any more
specific, since separation does the rest of the job for us to get to
the specific set w that we want.
It is not obvious to me that separation is powerful enough.
What if X is uncountable? We can only specify a countable
number of subsets of X. What if the subset we "want" can't
be specified with a finite formula?
And exactly which set do we want?
Saying "we don't need to be more specific" still sounds
like we are being deliberately vague. I think the reason
for vagueness is so we can "assume" the AoI set
contains limit ordinals (other than 0).
*** I know much less about this topic than you do,
I'm sure a lot of people disagree with you on this.
but it seems there is a
more fundamental reason for the vagueness of the definition of X. If anybody
could produce a specific such X, then they would have a model of ZF (a
collection of sets that satisfy ZF). This would prove the consistency of ZF.
AFAIK, there is no theoretical reason why such a set X could not be
described, but none ever has, and its seems pretty obvious that none ever
will. Hence the requirement to vague it up a bit.
We can derive omega from any set that satisfies AoI.
AoI says a set exists. It doesn't say more than one
such set exists. Since omega is defined as the "smallest"
set satisfying AoI, I see no reason to assume any
other set satisfies AoI.
Your argument suggests omega is a model of ZF.
Can't we prove omega exists in ZF?
I don't see how ZF can have a set with greater
cardinality than omega (without using Powerset).
Russell
- 2 many 2 count
.
- Follow-Ups:
- Re: Largest Set in ZFC?
- From: MoeBlee
- Re: Largest Set in ZFC?
- From: Peter Webb
- Re: Largest Set in ZFC?
- References:
- Largest Set in ZFC?
- From: reasterly
- Re: Largest Set in ZFC?
- From: MoeBlee
- Re: Largest Set in ZFC?
- From: reasterly
- Re: Largest Set in ZFC?
- From: MoeBlee
- Re: Largest Set in ZFC?
- From: Peter Webb
- Largest Set in ZFC?
- Prev by Date: Re: The rational number 5 and the real number 5
- Next by Date: Can I bisect an infinite sequence of numbers so that the bisection falls between 5 and 6?
- Previous by thread: Re: Largest Set in ZFC?
- Next by thread: Re: Largest Set in ZFC?
- Index(es):
Relevant Pages
|