Re: Equal Sets and Identical Sets
- From: MoeBlee <jazzmobe@xxxxxxxxxxx>
- Date: Mon, 10 Mar 2008 13:12:03 -0700 (PDT)
On Mar 10, 10:40 am, apoorv <sudhir...@xxxxxxxxxxx> wrote:
So, we have
p=q , but again p and q are not identical.
Yes, the axiom of extensionality works fine for 'e' interpreted as set
membership and doesn't work well at all for 'e' interpreted as certain
other relations.
What allows us to assert that the 'e' we
have in set theory ensures that equal sets are
identical sets ?
By interpreting it as the membership relation on a domain of sets.
How do we assert that there is
only one null set ( although all null sets may be equal )?
We prove the theorem
E!xAy ~yex.
If 'e' is interpreted as membership on a domain of sets, then the
above theorem is interpreted as there exists a unique set that has no
members.
How do we infer from A = B that {A} ={B}, unless we
assume that A and B are identical ?
Now, that is not a matter of set theory alone, but rather of identity
theory more basically. First, identity theory has axioms (including
one that reads roughly as "equals can be substituted for equals) from
which we prove
x=y -> {x}={y}.
Then, usually, '=' is taken to have a fixed interpretation so that '='
is always interpreted as the indicating the identity relation on the
universe of discourse.
It's been years that you've been posting about such subjects. I really
don't understand why you don't get a few good books on the subject so
that you could grab all this information right away, and in a
systematic way too.
MoeBlee
.
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