Re: The definition of finite set
- From: Fuckwit <nomail@invalid>
- Date: Tue, 11 Mar 2008 22:23:56 +0100
On Sat, 8 Mar 2008 19:43:52 -0800 (PST), Zaljohar@xxxxxxxxx wrote:
Since you actually DON'T KNOW if your definition is equivalent to the
Define:
x is finite iff [ card(x) = 0 or
(exists y (y << card(x)) and
for all y ((y < card(x) and y neq 0) implies exists z( z << y)))]
usual definitions of /finite/, you should define, say,
x is z-finite :<-> ...
See? So the QUESTION is:
Now the question is the following: Is this definition equivalent to
Dedekind definition of 'finite set'?
x is z-finite <-> x is Dedekind-finite ?
(for any x).
EITHER z-finite is equivalent to ALL definitions of /finiteness/ or with
IF not, then to which of the definitions of 'finite set' it is
equivalent?
NONE (in the context of ZFC, of course).
Now it's YOUR TURN to show that z-finite is equivalent to any of the
usual definitions of /finiteness/ in, say, ZFC. After all it's YOUR
proposal.
***
.
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