Re: Computable functions/reals.
- From: reasterly@xxxxxxxxx
- Date: Tue, 19 Aug 2008 21:40:14 -0700 (PDT)
On Aug 19, 3:43 am, David C. Ullrich <dullr...@xxxxxxxxxxx> wrote:
On Mon, 18 Aug 2008 19:15:46 -0700 (PDT), reaste...@xxxxxxxxx wrote:
Given two tapes, each with a Cauchy sequence written
as pairs of integers (like above), determine if the
two real numbers represented by these tapes differ
by more than 1/10.
In fact there are various details that have been unmentioned,
or mentioned only once or twice, in all this. When people
have said "Cauchy sequence" they actually mean, or
should mean, more than that here, namely a Cauchy
sequence _together with_ information on the rate of
convergence.
I don't know a word for that - the point is instead
of "Cauchy sequence converging to x" we should
really talk about something like "a sequence of
rationals r_j such that |x - r_| < 1/j for all j." Let's
agree to call that an "effective Cauchy sequence"
(there's probably a standard term for it that I
don't know).
I realize that the method of representing real numbers
is not central to your argument about computable
real functions.
You could use the factorial numbering system.
Every rational number has finite representation
in the factorial base. This would give a Cauchy
sequence with a rate of convergence of 1/n!.
I think my objection is more basic.
At this point I am not sure there are computable
functions for the natural numbers.
I can show that no sequential machine can
read or write more than a finite number of
positions from a tape. A sequential machine
is any machine that reads or writes one
character at a time.
Assume I am given an infinitely long tape.
This tape may unary representation of a natural
number (a string of non-blank characters followed
by a blank space) or it may contain no
non-blank characters.
Even an infinitely fast sequential machine can only
read a finite number of positions from this tape.
This means no sequenial machine can always
determine if the tape contains the representation
of a natural number.
I think this is enough to prove there exists
uncomputable natural numbers.
Russell
- Integers are an illusion
.
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