Re: Extrapolating linear ratios
- From: Herbert Newman <nomail@invalid>
- Date: Sun, 21 Dec 2008 06:14:21 +0100
On Sat, 20 Dec 2008 11:09:18 -0800 (PST) george wrote:
Right. If we have the _axiom of foundation_ the class of all sets (if we
But you really do need to remember that
there ALWAYS WAS, FROM THE BEGINNING,
A DIFFERENT possible resolution of this, namely,
TO DENY THE AXIOM OF FOUNDATION and to declare, from the beginning,
that OF COURSE a set of ALL sets would HAVE to contain itself as a
member.
have such a class in our set/class theory) cannot be a set. Simple as that.
Right. And there might be people who consider it only "natural" that sets
do not contain themselves as elements. (Hence in this case we do not even
need to refer to a "principle of size" for justifying that there's no
universal set in our set/class theory.)
Great. Though he already claimed in de.sci.mathematik that you actually DID
I am NOT defending the course he has ACTUALLY chosen.
that (concerning some other case). You may be sure that he will also use
your present claims for "defending" his views (by quoting them).
Herb
.
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- Extrapolating linear ratios
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- Re: Extrapolating linear ratios
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- Re: Extrapolating linear ratios
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- Re: Extrapolating linear ratios
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