Re: Non-denumerable ordinals
- From: David C. Ullrich <dullrich@xxxxxxxxxxx>
- Date: Tue, 07 Jul 2009 05:48:27 -0500
On Tue, 7 Jul 2009 02:00:39 -0700 (PDT), Marc Alcobé García
<malcobe@xxxxxxxxx> wrote:
On 6 jul, 15:31, Aatu Koskensilta <aatu.koskensi...@xxxxxx> wrote:
Yes. The countable ordinals are closed under pretty much any operation
you can think of.
So the method never collapses.
Which are the weakest assumptions needed in order to prove the
existence of an uncountable ordinal?
It seems that some sort of choice and replacement (so that P(omega)
can be well-ordered and shown to be order-isomorphic to some ordinal).
You don't need choice _or_ replacement to construct an
uncountable well-ordered _set_. I think then you need replacement
to get a (von Neumann) ordinal.
Say C is the set of pairs (E, <=), where E is a subset of omega and
<= is a well-ordering of E. Let W = C/~, where ~ is the equivalence
defined by isomorphism. Then W is uncountable, and W is well-
ordered by the relation "is isomophic to an initial segment of".
David C. Ullrich
"Understanding Godel isn't about following his formal proof.
That would make a mockery of everything Godel was up to."
(John Jones, "My talk about Godel to the post-grads."
in sci.logic.)
.
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