Re: Density of a porous particle knowing the mass of N particles

Mark Thorson wrote:

Uncle Al wrote:

Porosity wrote:

I know the mass of N porous particles and their mean diameter.
The volume of the particles is N*(PI*Dp^3)/6, where N is the number of
porous particles, PI is 3.14159... and Dp is the mean particle diameter.
To which kind of density the ratio mass/volume so obtained corresponds?
I need to determine the porous particle density (including pores) and
I know the pore volume (in cc/gram).

density = mass/volume

He's obviously NOT asking for the naive Newtonian
density. He wants the density corrected for pore
size, surface area, space curvature, and non-linearity,
as discussed here:

http://www.deanspacedrive.org/

density(particle) = mass/volume, corrected for bulk packing.

--
Uncle Al
http://www.mazepath.com/uncleal/
(Toxic URL! Unsafe for children and most mammals)
http://www.mazepath.com/uncleal/qz3.pdf
.

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