Re: better than a quartic?
From: Ken Turkowski (turk_at_worldserver.com)
Date: 07/08/04
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Date: Thu, 08 Jul 2004 04:25:52 GMT
In article <8360fe46.0407030617.37918510@posting.google.com>,
Carlo_02@libero.it (Carlo) wrote:
> I have to solve this set of equations:
>
> t5 = t1 + (t1-t2)^2/( (t1-t3)*(Pa-1) )
>
> t1 = t5 + (t5-t4)^1/( (t5-t3)*(Pb-1) )
>
> - is there a better way to solve the original equations, without
> turning them into a quartic? I need the 4 solutions, having only one
> won't do!
Isn't the resultant supposed to help with systems of polynomials? E.g.
the abstract of
http://portal.acm.org/citation.cfm?id=362839&dl=ACM&coll=portal
seems to imply so.
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