Re: Function Magic
From: Mehmet (m.dagdelen_at_free.fr)
Date: 07/19/04
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Date: 19 Jul 2004 01:28:23 -0700
jkaufman@shaw.ca (jk) wrote in message news:<ba27c48a.0407181634.44540e19@posting.google.com>...
> Hello:
>
> I have two function with the same domain, and a different ranges. Lets say
> they are f(a)=b , and g(a)=c. What I want is a new function such that
> h(b) = c. In other words h(f(a)) = c.
>
> I am not a mathamtician by any means, but I imagine there is a solution.
> I am just not sure about how to go about it. So, if someone can give
> me the methodology, I can make a run at starting to solve this.
>
> ps: this is not homework ;)
>
> John
-----If f is inversible---------
let's denote f^(-1) this inverse.
We have :
a=f^(-1)(b) and
g(a)=g(f^(-1)(b))= [gof^(-1)](b)=c
-- M
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