Re: A question on Newton's Method

On the Sun, 3 Apr 2005 15:42:00 -0600, James Van Buskirk wrote:
>> > f[x_] := x^3-x-1
>> > fp[x_] := D[f[x],x]
>> > Plot[fp[x],{x,-1,2}]
>
> When you finally figure out how to make this work you will
> have an excellent example of the true horror of Mathematica!

f[x_] := x^3 - x - 1
fp[x_] := D[f[s],s] /. s --> x
Plot[fp[x],{x, -1, 2}]

Which is in fact more compatible with the way mathematicians think (a
mathematician would have written:

fp(x) := df(s)/ds (x)

--
Roman Werpachowski
/--------==============--------\
| http://www.cft.edu.pl/~roman |
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.

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