Re: Complicated equation involving imaginaries...
- From: Anon <spamhole@xxxxxxxxxxxxxxxxx>
- Date: Wed, 14 Dec 2005 14:08:41 GMT
On Wed, 14 Dec 2005 07:02:29 EST, Jeff <jnoelcook@xxxxxxxxx> wrote:
>All,
>
>I really could use help with this. If F in the following equation can be solved for, I will have a solution for a problem very important to me. Honestly, I don't know what to do with it though at this point.
>
>i^2 = ( F / ( I^2 * i^2 )) + ( I^2 * i^2 ) + F
>
>Where I = ( E / F )
>Where E = 1.000040043
>What is F?
>
>I already know the answer for F in this case. It = 1.000043626. In other cases, I will need to use an equation to solve for it knowing only E.
>
>The above equation is the simplest I could get it down to. Using whole numbers with this equation, I = Sqrt {F}. However, this is not the case with the example above, or I believe any number other than whole numbers.
I don't understand this part about 'whole numbers' and I = Sqrt {F}.
You said above that I = ( E / F ).
>
>Any help with this would be greatly appreciated.
>
>Thanks,
>
>Jeff
It's best not to state part of the problem in the subject line.
In your equation, is (lowercase) i = sqrt(-1)? If so, i^2 = -1.
I may certainly have missed something, but if i^2 = -1 I get
F^5 - E^2 F^3 - E^2 F^2 + E^4 = 0
which is a fifth degree polynomial in F.
.
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