Re: imaginary cube root of one....what is it?
- From: Gordon Sande <g.sande@xxxxxxxxxxxxxxxx>
- Date: Wed, 12 Apr 2006 19:16:54 GMT
On 2006-04-12 15:11:34 -0300, "Wonkyungie" <wonkyungoglobal@xxxxxxxxx> said:
given a matrix:
1 w w^2 w^3
w w^2 w^3 1
w^2 w^3 1 w
w^3 1 w w^2
show that the deterinant is + - 3i(3^1/2)
where w^3=1
If w^3=1 then why do you have both w^3 and 1 as entries in the matrix?
Matrix is a 4x4 circulant so diagonalize it with a unitary transform
(hint: 4x4 Fourier matrix) and multiply the diagonal entries.
The use of w like this such smells of Fourier related homework!
Please make sure the instructor give credit where credit is due.
.
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- From: Wonkyungie
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