Re: Parametric center of pyramid

This is definitely the document I used most for my implementation,
thanks a lot for that. Unfortunately without Mathematica it is still
very difficult to read.
So in my case I simply compute the isoparametric center using the
coordinate of the point and I get:

Pyra5:
C: 2/5 , 2/5, 1/5

Pyra13:
C: 6/13, 6/13, 3/13

-M

.