Re: Probability of 1234567890

On Wed, 12 Jul 2006 02:41:04 GMT, Andrew Poelstra wrote:
On 2006-07-11, Stig Holmquist <stigfjorden@xxxxxxxxxxx> wrote:
What is the probability of drawing the digits
1-2-3-4-5-6-7-8-9-0 in any oder when sampling
ten times with replacement from an urn with ten
balls numbered 1-2-3-4-5-6-7-8-9-0 .

The probability of getting the same digit every
time would seem to be 1 per 10x10^10. So
to get the above set in any order must be
different. What formula should be used?


Well, the number of permutations of 1234567890 is 10!

So, you have 10!/(10x10^10)

The number of ways of selecting 10 balls when sampling with replacement
is 10^10, not 10^11.



--
Dave Seaman
U.S. Court of Appeals to review three issues
concerning case of Mumia Abu-Jamal.
<http://www.mumia2000.org/>
.

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