Re: ? determine common e-vector
- From: Robert Israel <israel@xxxxxxxxxxxxxxxxxxxxxxxxxxxxx>
- Date: Wed, 25 Jul 2007 17:45:07 -0500
"William R. Frensley" <frensley@xxxxxxxxxxxx> writes:
Cheng Cosine wrote:
Hi:Consider the concept of "simultaneously diagonalizable"
Suppose both matrices A and B and N-by-N and have
their own eigenvector decomposition. Suppose some
or all of their eigenvectors are common. How do we
determine those common eigenvector(s) shared by
A and B?
matrices, which means that two matrices can be diagonalized
by the same basis transformation. In other words, they share
the same eigenvectors. Now, simultaneously diagonalizable
matrices commute: AB - BA = 0.
If your matrices share some eigenvectors in common, I would
expect that their commutator C = [A,B] = AB-BA would reflect
this structure. The common eigenvectors should lie in the
null space of C. Therefore, I would suggest that you try
evaluating the commutator and then do SVD on the result to
identify its null space.
That's a start... but the common eigenvectors might not span all of the
null space of the commutator. You really need a subspace of that null
space that A and B map into itself.
--
Robert Israel israel@xxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Department of Mathematics http://www.math.ubc.ca/~israel
University of British Columbia Vancouver, BC, Canada
.
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