Re: x + 2x^2 + 4x^3 + 8x^4 + ... + 2^(k-1)x^k
- From: Praveen C <see.my.website@xxxxxxxxxxxxxxxx>
- Date: Mon, 28 Apr 2008 10:12:22 +0200
spasmous wrote:
Is anyone familiar with the MacLauren expansion x + 2x^2 + 4x^3 + 8x^4
+ ... + 2^(k-1)x^k ?
It is a geometric series with ratio (2x). So the sum is
x[ (2x)^k - 1 ]/[2x - 1]
Of course 2xS-S gives the answer directly.
--
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- From: spasmous
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