math reasoning:need help
- From: sne963@xxxxxxxxx
- Date: Sun, 7 Sep 2008 23:59:29 -0700 (PDT)
Why does any 3-digit number when multiplied by 7, and the result is
multiplied by 11 and the second result is multiplied by 13, gives the
original number 2 times?
For example, 112 is the original 3 digit number.
112*7= 784
784*11=8624
8624*13=112 112.
Please tell me why it happens with all 3 digit number? and why it is
only happen when multiplied by7,11 and 13( all of these are prime
numbers).
.
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