Re: equation please help

From: Robert Israel (israel_at_math.ubc.ca)
Date: 11/17/04


Date: 17 Nov 2004 08:15:01 -0500


In article <cnb0vu$2q3$1@dizzy.math.ohio-state.edu>,
Quick Function <quickcur@yahoo.com> wrote:

>What is the solution for the following equation:

>f(x, y) is a two dimensional function.

>|grad(f)| = g(x, y),

>grad is the gradient of f, g is a known function, | | is the norm.

Suppose p is an isolated zero of g. We may look for a solution
where p is a local minimum of f (of course, by symmetry f -> -f, this
could also be a local maximum; I don't know how to handle a saddle point
though). Then any point in some neighbourhood of p will lie on some
streamline of f that passes through p. For any curve C from p to q,
f(q) - f(p) = int_C grad(f).dr <= int_C g ds (where s is arc length),
with equality for the streamline. So, choosing an arbitrary value
for f(p), we define f(q) = f(p) + min_C int_C g ds, where the minimum
is taken over all rectifiable curves from p to q.

Robert Israel israel@math.ubc.ca
Department of Mathematics http://www.math.ubc.ca/~israel
University of British Columbia Vancouver, BC, Canada



Relevant Pages

  • Re: equation please help
    ... Suppose p is an isolated zero of g. ... where p is a local minimum of f (of course, by symmetry f -> -f, this ... streamline of f that passes through p. ... is taken over all rectifiable curves from p to q. ...
    (sci.math.symbolic)
  • Re: equation please help
    ... Suppose p is an isolated zero of g. ... where p is a local minimum of f (of course, by symmetry f -> -f, this ... streamline of f that passes through p. ... is taken over all rectifiable curves from p to q. ...
    (sci.math.num-analysis)