Re: Schur result on linear dimension
- From: Robin Chapman <rjc@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx>
- Date: Tue, 26 Apr 2005 15:30:04 +0000 (UTC)
William C Waterhouse wrote:
>
> In article <5227cf44.0504060538.649d3cc3@xxxxxxxxxxxxxxxxxx>,
> zellerg@xxxxxxxxxx (georgesZ) writes:
>> Hi,
>>
>> Can someone give here the proof of a Schur result :
>>
>> "for n>=1, the maximal linear dimension of a commutative subalgebra A
>> of the matrix algebra M_n(K) (K a commutative field) is [n^2/4]+1".
There's a 1998 note in the Monthly about this:
A Simple Proof of a Theorem of Schur
M. Mirzakhani
The American Mathematical Monthly, Vol. 105, No. 3. (Mar., 1998),
pp. 260-262.
Available on JSTOR at
http://links.jstor.org/sici?sici=0002-9890%28199803%29105%3A3%3C260%3AASPOAT%3E2.0.CO%3B2-R
--
Robin Chapman, www.maths.ex.ac.uk/~rjc/rjc.html
"Elegance is an algorithm"
Iain M. Banks, _The Algebraist_
.
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