Re: Hexpentaquaternions: a two-hand quaternion algebra



Hello,

I've always imagined the floretion algebra (over the
reals) as being something
like a "two-hand quaternion algebra".

I haven't had a chance to look at your paper yet, but
perhaps you'll find
http://www.crowdog.de/13829.html helpful.

Sincerely,
Creighton



Sincere thanks to Prof. Edwin Clark for sending me this enlightening message:


********

Let H denote the algebra of real quaternions and let o denote the tensor product symbol (x with a circle around it). Then

Floretions = H o H;
Hexpentaquaternions = H o H' where H' is H with the multiplication reversed.

But H is isomorphic to H' via conjugation of quaternions, so

Floretions = Hexpentaquaternions. (But with slightly different distinguished bases.)

.



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