Re: Mathematica simplification of (1+x)/x



In article <eFGme.3251$dN6.1032@xxxxxxxx>,
"Dave Snead" <dsnead6@xxxxxxxxxxx> wrote:

> In Mathematica 5.1, I tried simplifying
> (1+x)/x
> with the side condition
> 1+x+x^2==0
>
> using
> FullSimplify[(1+x)/x, 1+x+x^2==0]
>
> It should come out
> -x
>
> but Mathematica shows
> 1 + 1/x
>
> Is Mathematica not able to handle this easy simplification,
> or am I not using the FullSimplify command correctly?

You need to use Reduce:

Reduce[{(1+x)/x == y, 1+x+x^2==0}, y]

Cheers,
Paul

--
Paul Abbott Phone: +61 8 6488 2734
School of Physics, M013 Fax: +61 8 6488 1014
The University of Western Australia (CRICOS Provider No 00126G)
AUSTRALIA http://physics.uwa.edu.au/~paul
http://InternationalMathematicaSymposium.org/IMS2005/
.



Relevant Pages

  • Re: hypergeometric GF
    ... > That is just a formula for the coefficients but not the generating ... In Mathematica I tried ... Paul ... Prev by Date: ...
    (sci.math.symbolic)
  • Mathematica simplification of (1+x)/x
    ... In Mathematica 5.1, I tried simplifying ... Dave Snead ... Prev by Date: ...
    (sci.math.symbolic)
  • Re: A difficult hamiltonian problem
    ... Are there any stable fix points? ... but using Mathematica or Maple this is a very quick ... Prev by Date: ...
    (sci.math)
  • Root condition for polynomials
    ... If it can be done on mathematica what are the ... Regards, ... Terry ... Prev by Date: ...
    (sci.math.num-analysis)
  • Re: Sum of Gaussian functions
    ... To my mind (and with the help of mathematica) the expression ... of this nearly-constant periodic function could be: ... Valeri ... Prev by Date: ...
    (sci.math.num-analysis)