Re: maths


Maths For Fun And Insight wrote:
> me wrote:
> > There are 3 groups of coloured balls.group A consist 2 types white
> > balls.3 types red balls.group B contains 3 types blue balls & 1 type
> > white ball.& group C contain 1type red ball & 1 type blue ball.balls
> > should be picked up one after the other from the group A,B,C in the
> > same order when these 3 groups are mixed and prepare a set of group
> > with each group has three balls.
> >
> > A={w1,w2,R1,R2,R3}
> > B= {B1, B2, B3,W3}
> > C= {R4, B4}
> >
> > 1.how many groups will have 2 white balls & 1 red balls?
> > 2.how many groups will have 3 white balls?
> > 3.how many groups having 2 white balls?
>
> If you take 1 from A, 1 from B, and 1 from C, you have 5x4x3 = 40
> combinations. Of these, the following have 2 white balls and one red
> ball:
>
> W1 W3 R4
> W2 W3 R4
>
> It is not possible to make a group of 3 white balls with one ball each
> from A,B,C.
>
> There are four combinations with 2 white balls:
>
> W1 W3 R4
> W2 W3 R4
> W1 W3 B4
> W2 W3 B4
>
> > How can I solve the problem? Please explain it & post the detailed
> > messege with definition step by step.
>
> "Multiplication".
>
> > bye

This question is retarded. It looks like you solved it by counting but
in this case it could of equally been solvable though multiplication.
It would be much more interesting if group C had white ball two and
then from the example you were suppose to deduce some kind of general
expression. Also this problem has nothing to do with sci.math.symbolic.

.

Quantcast