Re: Simplifying in Mathematica
- From: Jean-Marc Gulliet <jeanmarc.gulliet@xxxxxxxxx>
- Date: Wed, 08 Nov 2006 08:06:07 +0100
330006@xxxxxxxxx wrote:
I have a function which is a sum of many terms which look like this:Not knowing the real expression, I can only guess. If the function is a sum of rational expression, it will be equal to zero if its numerator is itself equal to zero. So you could start by extracting the numerator of the function and from there try to simplify it further (Simplify, Expand, PowerExpand, and the like).
(2*(B-b)^2 - 2*(A-a)*c*d^2)/(4*b^2*(1-c*2)*d^2)
I think the function is actually equal to 0, but I have a hard time in
trying to simplify it in Mathematica. Any ideas or commands I should
try?
Thanks a lot!
In[1]:=
expr = (2*(B - b)^2 - 2*(A - a)*c*d^2)/(4*b^2*(1 - c*2)*d^2)
Out[1]=
2 2
2 (-b + B) - 2 (-a + A) c d
-----------------------------
2 2
4 b (1 - 2 c) d
In[2]:=
Numerator[expr]
Out[2]=
2 2
2 (-b + B) - 2 (-a + A) c d
Regards,
Jean-Marc
.
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