Re: Fourier trasnsform in Maple

dimitris <dimmechan@xxxxxxxxx> writes:

Am I doing something wrong?

with(inttrans):
1/2*fourier(sech(x*a),x,s)*2^(1/2)/Pi^(1/2);

1/2
fourier(sech(x a), x, s) 2
1/2 -----------------------------
1/2
Pi

Maple's "fourier" relies on a rather limited repertoire of known transforms,
and apparently sech isn't in that repertoire.
--
Robert Israel israel@xxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Department of Mathematics http://www.math.ubc.ca/~israel
University of British Columbia Vancouver, BC, Canada
.