Re: [Maxima] Newbie question
- From: Peter Pein <petsie@xxxxxxxxxx>
- Date: Tue, 08 Apr 2008 15:08:16 +0200
Olivier schrieb:
....
My aim today:
integrate(1/t*integrate(1/u*(2*u/t-u^2/t^2,u,eps,t),t,eps,1)
with eps in ]0,1[.
Help appreciated :-p
Best,
Amities,
Olivier
/*wxMaxima 0.7.4 http://wxmaxima.sourceforge.netMaxima 5.14.0
http://maxima.sourceforge.netUsing Lisp GNU Common Lisp (GCL) GCL 2.6.7 (aka
GCL)Distributed under the GNU Public License. See the file COPYING.Dedicated
to the memory of William Schelter.The function bug_report() provides bug
reporting information.
(%i1) assume(0<a,a<1);
(%o1) [a>0,a<1]
(%i2) integrate(1/u,u,1,a);
(%o2) log(a)
(%i3) assume(eps>0,eps<1);
(%o3) [eps>0,eps<1]
(%i4) integrate(1/t*integrate(1/u*(2*u/t-u^2/t^2),u,eps,t),t,eps,1);
Is t-eps positive, negative, or zero?
p;
(%o4) -(3*log(eps))/2+(8*eps-eps^2)/4-7/4
this is not too difficult ;-)
I guessed where the missing closing paranthesis should be.
Peter
.
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