Re: (c+y)² + (-y+c-x)² + (x+c)Q_=3D_=28c-y=29=B2_+_=28y+c+x=29=B2_+_=28-x+c?= Q=B2?=
From: William Elliot (marsh_at_privacy.net)
Date: 06/10/04
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Date: Wed, 9 Jun 2004 23:13:52 -0700
On Thu, 10 Jun 2004, Gerry Myerson wrote:
> "RASINGER" <helmut_rasinger@hotmail.com> wrote:
>
> > (c+y)² + (-y+c-x)² + (x+c)² = (c-y)² + (y+c+x)² + (-x+c)²
>
> I take it that what looks like quotation marks on my screen
> are really supposed to be superscript twos, so we're talking
> about a sum-of-squares identity. See Gloden, Mehrgradige Gleichungen.
>
On my screen those "quotation marks" appeared as shaded rectangles.
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