Find point given 2 points
From: Michael Hill (hillmw_at_ram.lmtas.lmco.com)
Date: 06/24/04
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Date: Thu, 24 Jun 2004 15:35:23 -0500
Two questions about finding the 3rd point:
I have a line consisting of the coordinates (4,6) and (12,2).
The midpoint of the line can be calculated as (8,4) using the
midpoint formula.
A right triangle is formed at the midpoint (8,4).
1) Using 2 points (8,4) and point (12,2) and the lengths of the legs
I'd like to find the 3rd point.
Assume the following data:
The small leg of the triangle is formed from (8,4) to (12,2) (call
this leg b).
The large leg of the triangle has a length of 10 (call this leg a).
2) Using 2 points (8,4) and point (12,2) and the angles of the
triangle I'd like to find the 3rd point.
Assume the following data:
The small leg of the triangle is formed from (8,4) to (12,2) (call
this leg b). This is a 30,60,90 triangle.
Can't figure out the last step
In solving 1) I can calculate the length of the hypotenuse (call this
leg c) as:
10^2 + 4^2 = c^2
100 + 16 = c^2
10.77 = c
Since I know the length of all the legs and 2 points I should be able
to apply a formula to it.
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