Re: log function comparison

From: phil (pfreedenberg_at_hotmail.com)
Date: 07/01/04 

Date: Thu, 1 Jul 2004 19:07:31 +0000 (UTC)

On 01 Jul 2004, airnikez wrote:
>how do I compare these functions below and figure out which one is faster than the other.. i'm using O notation..
>
>n^2(2^n) 3^n
>
>n^(1/3) (logn)^6
>
>I need to know the relationship between the 2 functions. Is it big O, small o, omega, theta, micron?
>
>Thanks.

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