Re: JSH: Groupthink

From: James Harris (jstevh_at_msn.com)
Date: 07/19/04 

Date: 19 Jul 2004 06:34:17 -0700

akolowski@hotmail.com (Andrzej Kolowski) wrote in message news:<a1fa83d9.0407181325.3247cfd0@posting.google.com>...
> jstevh@msn.com (James Harris) wrote in message news:<3c65f87.0407180744.56169642@posting.google.com>...

<deleted>

> >> Fraud is when you submit a paper like this to a journal knowing
> >> it has this kind of error; or fail to withdraw the paper when
> >> such errors and others have been pointed out. That is outright
> >> academic fraud, the kind that gets people fired from tenured
> >> positions. Harris has no worries on that score.
> >
> >Well, I can see you are emotionally involved, but sometimes a mistake
> >is just a mistake.
> >
>
> The question is, have you withdrawn the paper? Until you have,
> you are committing fraud and I will continue to remind you of it.
>

Minor errors do not require withdrawal of a paper.

What *should* have happened with SWJPAM is that they noticed the error
and asked if I could correct it, but they never did.

The errors are basically typos that don't change the conclusion. I'm
curious to see if you'll admit that reality.

>
> >The fix here is easy enough. As you noted I should have
> >
> >(m^3 f^6 - 3m^2 f^4 + 3m f^2)x^3 - 3(-1 + mf^2)xu^2 f^2 + u^3 f^3
> >
> >where letting y = uf gives
> >
> >(m^3 f^6 - 3m^2 f^4 + 3m f^2)x^3 - 3(-1 + mf^2)xy^2 + y^3
> >
> >and I consider the factorization so I have
> >
> >(m^3 f^6 - 3m^2 f^4 + 3m f^2)x^3 - 3(-1 + mf^2)xy^2 + y^3 =
> >
> > (a_1 x + y)(a_2 x + y)(a_3 x + y)
> >
> >and I hope you'd agree that the value of y doesn't affect the values
> >of a_1, a_2 and a_3,
>
>
> *Of course* it does. It's obvious: -y/a_1 is a root of the polynomial.
> If y changes, a_1 must also change.
>

That is incorrect.

Let me give you an example:

(2x + y)(3x + y) = 6x^2 + 5xy + y^2

Now then, does the value of y change the values of the first
coefficient of

2x + y and 3x + y?

Of course it does not.

You didn't find a major error, just typos.

Given

(m^3 f^6 - 3m^2 f^4 + 3m f^2)x^3 - 3(-1 + mf^2)xy^2 + y^3 =

      (a_1 x + y)(a_2 x + y)(a_3 x + y)

the value of the a's is independent of the value of y, just like 2 and
3 are independent of the value of y with

(2x + y)(3x + y) = 6x^2 + 5xy + y^2

but I want to emphasize something for others using this poster.

>
> >so I can arbitrarily set y=1, and use the
> >conclusion already derived in the paper for the a's, so that I know it
> >applies to
> >
> >65 x^3 - 12 x + 1
> >
> >with f=sqrt(5), m=1.
> >
>
> Here is your prior statement in APF:
>
> "Here f is a non unit, non zero algebraic integer coprime
> to 3 and x, and u a non unit, non zero algebraic integer
> coprime to f."
>
> Now you say above, y = uf, y = 1, and f = sqrt(5). That amounts to
> assuming
>
> 1 = u * sqrt(5),
>
> where u is a *non unit, non zero algebraic integer*.
>
> Need I go on ? Or do you want to keep digging a deeper hole
> for yourself ?
>
> Andrzej

Notice that the poster Andrzej Kolowski is lost on basic algebra. It
turns out that while I did use y=uf at various places in the paper,
the value of y is actually independent of the values of the a's.

It's a minor point relying on basic algebra as I demonstrated with

(2x + y)(3x + y) = 6x^2 + 5xy + y^2

but here this poster is accusing me of fraud, and asking me to
withdraw a major paper.

What can you do in the face of such irrationality?

There's no stopping these posters from going on with their wrong
positions, and oddly enough, other posters on the group tend to just
support them, or ignore it when they go off into bizarrely wrong
mathematical positions.

The newsgroup is clearly not really about math.

James Harris

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